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11403011140214 = 25701505570107
BaseRepresentation
bin1010010111101111100001…
…1011011010101001110110
31111101010011110012211010212
42211323320123122221312
52443311331322441324
640130245422545422
72254561150305641
oct245737033325166
944333143184125
1011403011140214
1136a6a98570541
121341b91438272
136493b7847465
142b5ca1600a58
1514b9425e770e
hexa5ef86daa76

11403011140214 has 4 divisors (see below), whose sum is σ = 17104516710324. Its totient is φ = 5701505570106.

The previous prime is 11403011140207. The next prime is 11403011140229. The reversal of 11403011140214 is 41204111030411.

It is a semiprime because it is the product of two primes.

It is a self number, because there is not a number n which added to its sum of digits gives 11403011140214.

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2850752785052 + ... + 2850752785055.

It is an arithmetic number, because the mean of its divisors is an integer number (4276129177581).

Almost surely, 211403011140214 is an apocalyptic number.

11403011140214 is a deficient number, since it is larger than the sum of its proper divisors (5701505570110).

11403011140214 is an equidigital number, since it uses as much as digits as its factorization.

11403011140214 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 5701505570109.

The product of its (nonzero) digits is 384, while the sum is 23.

Adding to 11403011140214 its reverse (41204111030411), we get a palindrome (52607122170625).

The spelling of 11403011140214 in words is "eleven trillion, four hundred three billion, eleven million, one hundred forty thousand, two hundred fourteen".

Divisors: 1 2 5701505570107 11403011140214