Base | Representation |
---|---|
bin | 10000100101111111011… |
… | …000011000011001010001 |
3 | 11001000022201002012122122 |
4 | 100211333120120121101 |
5 | 122140320134244444 |
6 | 2231503111544025 |
7 | 145245532145363 |
oct | 20457730303121 |
9 | 4030281065578 |
10 | 1140303431249 |
11 | 3aa666617464 |
12 | 164bb938b015 |
13 | 836b798a348 |
14 | 3d29609cd33 |
15 | 1e9dde234ee |
hex | 1097f618651 |
1140303431249 has 2 divisors, whose sum is σ = 1140303431250. Its totient is φ = 1140303431248.
The previous prime is 1140303431233. The next prime is 1140303431257. The reversal of 1140303431249 is 9421343030411.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 1118263950400 + 22039480849 = 1057480^2 + 148457^2 .
It is a cyclic number.
It is not a de Polignac number, because 1140303431249 - 24 = 1140303431233 is a prime.
It is not a weakly prime, because it can be changed into another prime (1140303431279) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570151715624 + 570151715625.
It is an arithmetic number, because the mean of its divisors is an integer number (570151715625).
Almost surely, 21140303431249 is an apocalyptic number.
It is an amenable number.
1140303431249 is a deficient number, since it is larger than the sum of its proper divisors (1).
1140303431249 is an equidigital number, since it uses as much as digits as its factorization.
1140303431249 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 31104, while the sum is 35.
The spelling of 1140303431249 in words is "one trillion, one hundred forty billion, three hundred three million, four hundred thirty-one thousand, two hundred forty-nine".
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