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11403054410215 = 513213494738947
BaseRepresentation
bin1010010111101111101100…
…0000011110100111100111
31111101010021110122011102111
42211323323000132213213
52443311423412111330
640130254010221451
72254562214143356
oct245737300364747
944333243564374
1011403054410215
1136a700aa34976
121341ba3a24887
136493c37b7500
142b5ca726599d
1514b9462e332a
hexa5efb01e9e7

11403054410215 has 12 divisors (see below), whose sum is σ = 14817223364904. Its totient is φ = 8420717102304.

The previous prime is 11403054410213. The next prime is 11403054410239. The reversal of 11403054410215 is 51201445030411.

It is not a de Polignac number, because 11403054410215 - 21 = 11403054410213 is a prime.

It is a super-2 number, since 2×114030544102152 (a number of 27 digits) contains 22 as substring.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11403054410213) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 6747368629 + ... + 6747370318.

It is an arithmetic number, because the mean of its divisors is an integer number (1234768613742).

Almost surely, 211403054410215 is an apocalyptic number.

11403054410215 is a deficient number, since it is larger than the sum of its proper divisors (3414168954689).

11403054410215 is a wasteful number, since it uses less digits than its factorization.

11403054410215 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 13494738978 (or 13494738965 counting only the distinct ones).

The product of its (nonzero) digits is 9600, while the sum is 31.

Adding to 11403054410215 its reverse (51201445030411), we get a palindrome (62604499440626).

The spelling of 11403054410215 in words is "eleven trillion, four hundred three billion, fifty-four million, four hundred ten thousand, two hundred fifteen".

Divisors: 1 5 13 65 169 845 13494738947 67473694735 175431606311 877158031555 2280610882043 11403054410215