Base | Representation |
---|---|
bin | 1010010111101111101100… |
… | …0000011110100111111111 |
3 | 1111101010021110122011110101 |
4 | 2211323323000132213333 |
5 | 2443311423412111424 |
6 | 40130254010221531 |
7 | 2254562214143422 |
oct | 245737300364777 |
9 | 44333243564411 |
10 | 11403054410239 |
11 | 36a700aa34998 |
12 | 1341ba3a248a7 |
13 | 6493c37b751b |
14 | 2b5ca72659b9 |
15 | 14b9462e3344 |
hex | a5efb01e9ff |
11403054410239 has 2 divisors, whose sum is σ = 11403054410240. Its totient is φ = 11403054410238.
The previous prime is 11403054410213. The next prime is 11403054410249. The reversal of 11403054410239 is 93201445030411.
It is a strong prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-11403054410239 is a prime.
It is a super-2 number, since 2×114030544102392 (a number of 27 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 11403054410198 and 11403054410207.
It is a congruent number.
It is not a weakly prime, because it can be changed into another prime (11403054410249) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5701527205119 + 5701527205120.
It is an arithmetic number, because the mean of its divisors is an integer number (5701527205120).
Almost surely, 211403054410239 is an apocalyptic number.
11403054410239 is a deficient number, since it is larger than the sum of its proper divisors (1).
11403054410239 is an equidigital number, since it uses as much as digits as its factorization.
11403054410239 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 51840, while the sum is 37.
The spelling of 11403054410239 in words is "eleven trillion, four hundred three billion, fifty-four million, four hundred ten thousand, two hundred thirty-nine".
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