Base | Representation |
---|---|
bin | 10101001111010110… |
… | …11010111011001101 |
3 | 1002102200222010010201 |
4 | 22213223122323031 |
5 | 141323144042031 |
6 | 5123304133501 |
7 | 552402565621 |
oct | 124753327315 |
9 | 32380863121 |
10 | 11403112141 |
11 | 4921839a23 |
12 | 2262a67291 |
13 | 10c95b8645 |
14 | 7a2645181 |
15 | 46b169d61 |
hex | 2a7adaecd |
11403112141 has 4 divisors (see below), whose sum is σ = 11405079612. Its totient is φ = 11401144672.
The previous prime is 11403112099. The next prime is 11403112153. The reversal of 11403112141 is 14121130411.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 7668680041 + 3734432100 = 87571^2 + 61110^2 .
It is a cyclic number.
It is not a de Polignac number, because 11403112141 - 211 = 11403110093 is a prime.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11403112541) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 975016 + ... + 986641.
It is an arithmetic number, because the mean of its divisors is an integer number (2851269903).
Almost surely, 211403112141 is an apocalyptic number.
It is an amenable number.
11403112141 is a deficient number, since it is larger than the sum of its proper divisors (1967471).
11403112141 is an equidigital number, since it uses as much as digits as its factorization.
11403112141 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 1967470.
The product of its (nonzero) digits is 96, while the sum is 19.
Adding to 11403112141 its reverse (14121130411), we get a palindrome (25524242552).
The spelling of 11403112141 in words is "eleven billion, four hundred three million, one hundred twelve thousand, one hundred forty-one".
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