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11403112141 = 58131961657
BaseRepresentation
bin10101001111010110…
…11010111011001101
31002102200222010010201
422213223122323031
5141323144042031
65123304133501
7552402565621
oct124753327315
932380863121
1011403112141
114921839a23
122262a67291
1310c95b8645
147a2645181
1546b169d61
hex2a7adaecd

11403112141 has 4 divisors (see below), whose sum is σ = 11405079612. Its totient is φ = 11401144672.

The previous prime is 11403112099. The next prime is 11403112153. The reversal of 11403112141 is 14121130411.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 7668680041 + 3734432100 = 87571^2 + 61110^2 .

It is a cyclic number.

It is not a de Polignac number, because 11403112141 - 211 = 11403110093 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11403112541) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 975016 + ... + 986641.

It is an arithmetic number, because the mean of its divisors is an integer number (2851269903).

Almost surely, 211403112141 is an apocalyptic number.

It is an amenable number.

11403112141 is a deficient number, since it is larger than the sum of its proper divisors (1967471).

11403112141 is an equidigital number, since it uses as much as digits as its factorization.

11403112141 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 1967470.

The product of its (nonzero) digits is 96, while the sum is 19.

Adding to 11403112141 its reverse (14121130411), we get a palindrome (25524242552).

The spelling of 11403112141 in words is "eleven billion, four hundred three million, one hundred twelve thousand, one hundred forty-one".

Divisors: 1 5813 1961657 11403112141