11403113 has 2 divisors, whose sum is σ = 11403114. Its totient is φ = 11403112.

The previous prime is 11403103. The next prime is 11403131. The reversal of 11403113 is 31130411.

Together with next prime (11403131) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 11202409 + 200704 = 3347^2 + 448^2 .

It is a cyclic number.

It is not a de Polignac number, because 11403113 - 2⁸ = 11402857 is a prime.

It is a Chen prime.

It is not a weakly prime, because it can be changed into another prime (11403103) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5701556 + 5701557.

It is an arithmetic number, because the mean of its divisors is an integer number (5701557).

Almost surely, 2^11403113 is an apocalyptic number.

It is an amenable number.

11403113 is a deficient number, since it is larger than the sum of its proper divisors (1).

11403113 is an equidigital number, since it uses as much as digits as its factorization.

11403113 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 36, while the sum is 14.

The square root of 11403113 is about 3376.8495672742. The cubic root of 11403113 is about 225.0821954836.

Adding to 11403113 its reverse (31130411), we get a palindrome (42533524).

The spelling of 11403113 in words is "eleven million, four hundred three thousand, one hundred thirteen".