Base | Representation |
---|---|
bin | 1010010111101111111110… |
… | …1010000010000111110010 |
3 | 1111101010110220102002022101 |
4 | 2211323333222002013302 |
5 | 2443312103344144102 |
6 | 40130305434131014 |
7 | 2254564152146113 |
oct | 245737752020762 |
9 | 44333426362271 |
10 | 11403132412402 |
11 | 36a704aa71095 |
12 | 1342005b80a6a |
13 | 6494069c8453 |
14 | 2b5cb376c20a |
15 | 14b94d09ee87 |
hex | a5effa821f2 |
11403132412402 has 4 divisors (see below), whose sum is σ = 17104698618606. Its totient is φ = 5701566206200.
The previous prime is 11403132412391. The next prime is 11403132412429. The reversal of 11403132412402 is 20421423130411.
It is a happy number.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 8617107411081 + 2786025001321 = 2935491^2 + 1669139^2 .
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 2850783103099 + ... + 2850783103102.
Almost surely, 211403132412402 is an apocalyptic number.
11403132412402 is a deficient number, since it is larger than the sum of its proper divisors (5701566206204).
11403132412402 is an equidigital number, since it uses as much as digits as its factorization.
11403132412402 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 5701566206203.
The product of its (nonzero) digits is 4608, while the sum is 28.
Adding to 11403132412402 its reverse (20421423130411), we get a palindrome (31824555542813).
The spelling of 11403132412402 in words is "eleven trillion, four hundred three billion, one hundred thirty-two million, four hundred twelve thousand, four hundred two".
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