Base | Representation |
---|---|
bin | 10000100110000000011… |
… | …000000001010111011001 |
3 | 11001000100212110210021101 |
4 | 100212000120001113121 |
5 | 122140333422123022 |
6 | 2231504505311401 |
7 | 145246124020501 |
oct | 20460030012731 |
9 | 4030325423241 |
10 | 1140320114137 |
11 | 3aa674a81576 |
12 | 165002a95561 |
13 | 836bb27b989 |
14 | 3d2983a2a01 |
15 | 1e9e061b627 |
hex | 109806015d9 |
1140320114137 has 2 divisors, whose sum is σ = 1140320114138. Its totient is φ = 1140320114136.
The previous prime is 1140320114083. The next prime is 1140320114161. The reversal of 1140320114137 is 7314110230411.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 947778184521 + 192541929616 = 973539^2 + 438796^2 .
It is an emirp because it is prime and its reverse (7314110230411) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1140320114137 is a prime.
It is not a weakly prime, because it can be changed into another prime (1140320114837) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570160057068 + 570160057069.
It is an arithmetic number, because the mean of its divisors is an integer number (570160057069).
Almost surely, 21140320114137 is an apocalyptic number.
It is an amenable number.
1140320114137 is a deficient number, since it is larger than the sum of its proper divisors (1).
1140320114137 is an equidigital number, since it uses as much as digits as its factorization.
1140320114137 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 2016, while the sum is 28.
Adding to 1140320114137 its reverse (7314110230411), we get a palindrome (8454430344548).
The spelling of 1140320114137 in words is "one trillion, one hundred forty billion, three hundred twenty million, one hundred fourteen thousand, one hundred thirty-seven".
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