114032013000000 has 392 divisors, whose sum is σ = 377296613041536. Its totient is φ = 30395289600000.

The previous prime is 114032012999969. The next prime is 114032013000067. The reversal of 114032013000000 is 310230411.

It is a Harshad number since it is a multiple of its sum of digits (15).

It is a congruent number.

It is an unprimeable number.

It is a polite number, since it can be written in 55 ways as a sum of consecutive naturals, for example, 8258993097 + ... + 8259006903.

Almost surely, 2^{114032013000000} is an apocalyptic number.

114032013000000 is a gapful number since it is divisible by the number (10) formed by its first and last digit.

It is an amenable number.

It is a practical number, because each smaller number is the sum of distinct divisors of 114032013000000, and also a Zumkeller number, because its divisors can be partitioned in two sets with the same sum (188648306520768).

114032013000000 is an abundant number, since it is smaller than the sum of its proper divisors (263264600041536).

It is a pseudoperfect number, because it is the sum of a subset of its proper divisors.

114032013000000 is an frugal number, since it uses more digits than its factorization.

114032013000000 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 16605 (or 16570 counting only the distinct ones).

The product of its (nonzero) digits is 72, while the sum is 15.

Adding to 114032013000000 its reverse (310230411), we get a palindrome (114032323230411).

The spelling of 114032013000000 in words is "one hundred fourteen trillion, thirty-two billion, thirteen million", and thus it is an aban number.