Base | Representation |
---|---|
bin | 11001111011011001100011… |
… | …101001100100110110110011 |
3 | 112221202110020120022220100202 |
4 | 121323121203221210312303 |
5 | 104421304143202131201 |
6 | 1042310021150105415 |
7 | 33006421241214644 |
oct | 3173314351446663 |
9 | 487673216286322 |
10 | 114033053552051 |
11 | 33375167992727 |
12 | 10958452aab26b |
13 | 4b82369c765ca |
14 | 202332d0716cb |
15 | d2b3dc417c6b |
hex | 67b663a64db3 |
114033053552051 has 4 divisors (see below), whose sum is σ = 114033115872312. Its totient is φ = 114032991231792.
The previous prime is 114033053551957. The next prime is 114033053552053. The reversal of 114033053552051 is 150255350330411.
It is a semiprime because it is the product of two primes.
It is a cyclic number.
It is not a de Polignac number, because 114033053552051 - 230 = 114031979810227 is a prime.
It is a Duffinian number.
It is a junction number, because it is equal to n+sod(n) for n = 114033053551996 and 114033053552014.
It is not an unprimeable number, because it can be changed into a prime (114033053552053) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 28329746 + ... + 32103591.
It is an arithmetic number, because the mean of its divisors is an integer number (28508278968078).
Almost surely, 2114033053552051 is an apocalyptic number.
114033053552051 is a deficient number, since it is larger than the sum of its proper divisors (62320261).
114033053552051 is an equidigital number, since it uses as much as digits as its factorization.
114033053552051 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 62320260.
The product of its (nonzero) digits is 135000, while the sum is 38.
The spelling of 114033053552051 in words is "one hundred fourteen trillion, thirty-three billion, fifty-three million, five hundred fifty-two thousand, fifty-one".
• e-mail: info -at- numbersaplenty.com • Privacy notice • done in 0.090 sec. • engine limits •