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114033053552053 is a prime number
BaseRepresentation
bin11001111011011001100011…
…101001100100110110110101
3112221202110020120022220100211
4121323121203221210312311
5104421304143202131203
61042310021150105421
733006421241214646
oct3173314351446665
9487673216286324
10114033053552053
1133375167992729
1210958452aab271
134b82369c765cc
14202332d0716cd
15d2b3dc417c6d
hex67b663a64db5

114033053552053 has 2 divisors, whose sum is σ = 114033053552054. Its totient is φ = 114033053552052.

The previous prime is 114033053551957. The next prime is 114033053552059. The reversal of 114033053552053 is 350255350330411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 108306523189764 + 5726530362289 = 10407042^2 + 2393017^2 .

It is a cyclic number.

It is not a de Polignac number, because 114033053552053 - 213 = 114033053543861 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 114033053551997 and 114033053552015.

It is a congruent number.

It is not a weakly prime, because it can be changed into another prime (114033053552059) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57016526776026 + 57016526776027.

It is an arithmetic number, because the mean of its divisors is an integer number (57016526776027).

Almost surely, 2114033053552053 is an apocalyptic number.

It is an amenable number.

114033053552053 is a deficient number, since it is larger than the sum of its proper divisors (1).

114033053552053 is an equidigital number, since it uses as much as digits as its factorization.

114033053552053 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 405000, while the sum is 40.

The spelling of 114033053552053 in words is "one hundred fourteen trillion, thirty-three billion, fifty-three million, five hundred fifty-two thousand, fifty-three".