Base | Representation |
---|---|
bin | 110101000110011110… |
… | …1001111011110100001 |
3 | 101220100020010010102012 |
4 | 1222030331033132201 |
5 | 3332020201422423 |
6 | 124215252402305 |
7 | 11144604061355 |
oct | 1521475173641 |
9 | 356306103365 |
10 | 114034014113 |
11 | 443a8256678 |
12 | 1a125916395 |
13 | a9a419a6c6 |
14 | 573ac6d465 |
15 | 2e7633b078 |
hex | 1a8cf4f7a1 |
114034014113 has 2 divisors, whose sum is σ = 114034014114. Its totient is φ = 114034014112.
The previous prime is 114034014091. The next prime is 114034014163. The reversal of 114034014113 is 311410430411.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 75621150049 + 38412864064 = 274993^2 + 195992^2 .
It is a cyclic number.
It is not a de Polignac number, because 114034014113 - 214 = 114033997729 is a prime.
It is not a weakly prime, because it can be changed into another prime (114034014163) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57017007056 + 57017007057.
It is an arithmetic number, because the mean of its divisors is an integer number (57017007057).
Almost surely, 2114034014113 is an apocalyptic number.
It is an amenable number.
114034014113 is a deficient number, since it is larger than the sum of its proper divisors (1).
114034014113 is an equidigital number, since it uses as much as digits as its factorization.
114034014113 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 576, while the sum is 23.
Adding to 114034014113 its reverse (311410430411), we get a palindrome (425444444524).
The spelling of 114034014113 in words is "one hundred fourteen billion, thirty-four million, fourteen thousand, one hundred thirteen".
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