1140341322433 has 2 divisors, whose sum is σ = 1140341322434. Its totient is φ = 1140341322432.

The previous prime is 1140341322409. The next prime is 1140341322469. The reversal of 1140341322433 is 3342231430411.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 1032483596544 + 107857725889 = 1016112^2 + 328417^2 .

It is a cyclic number.

It is not a de Polignac number, because 1140341322433 - 2⁵ = 1140341322401 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1140341322395 and 1140341322404.

It is not a weakly prime, because it can be changed into another prime (1140341322473) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570170661216 + 570170661217.

It is an arithmetic number, because the mean of its divisors is an integer number (570170661217).

Almost surely, 2^{1140341322433} is an apocalyptic number.

It is an amenable number.

1140341322433 is a deficient number, since it is larger than the sum of its proper divisors (1).

1140341322433 is an equidigital number, since it uses as much as digits as its factorization.

1140341322433 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 20736, while the sum is 31.

Adding to 1140341322433 its reverse (3342231430411), we get a palindrome (4482572752844).

The spelling of 1140341322433 in words is "one trillion, one hundred forty billion, three hundred forty-one million, three hundred twenty-two thousand, four hundred thirty-three".