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1140343002137 is a prime number
BaseRepresentation
bin10000100110000001101…
…111010101010000011001
311001000102110112121201002
4100212001233111100121
5122140410302032022
62231511044034345
7145246522405403
oct20460157252031
94030373477632
101140343002137
113aa686994679
1216500a6929b5
13836c2c33781
143d29b43db73
151e9e263d092
hex10981bd5419

1140343002137 has 2 divisors, whose sum is σ = 1140343002138. Its totient is φ = 1140343002136.

The previous prime is 1140343002109. The next prime is 1140343002151. The reversal of 1140343002137 is 7312003430411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 1110601930201 + 29741071936 = 1053851^2 + 172456^2 .

It is a cyclic number.

It is not a de Polignac number, because 1140343002137 - 210 = 1140343001113 is a prime.

It is not a weakly prime, because it can be changed into another prime (1140343002187) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570171501068 + 570171501069.

It is an arithmetic number, because the mean of its divisors is an integer number (570171501069).

Almost surely, 21140343002137 is an apocalyptic number.

It is an amenable number.

1140343002137 is a deficient number, since it is larger than the sum of its proper divisors (1).

1140343002137 is an equidigital number, since it uses as much as digits as its factorization.

1140343002137 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 6048, while the sum is 29.

Adding to 1140343002137 its reverse (7312003430411), we get a palindrome (8452346432548).

The spelling of 1140343002137 in words is "one trillion, one hundred forty billion, three hundred forty-three million, two thousand, one hundred thirty-seven".