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114034422013 = 359331737941
BaseRepresentation
bin110101000110011111…
…0110011000011111101
3101220100020212211221121
41222030332303003331
53332020303001023
6124215305230541
711144610410521
oct1521476630375
9356306784847
10114034422013
11443a8505086
121a125a92451
13a9a42b1275
14573ad37d81
152e763bbd5d
hex1a8cfb30fd

114034422013 has 4 divisors (see below), whose sum is σ = 114066163548. Its totient is φ = 114002680480.

The previous prime is 114034421993. The next prime is 114034422023. The reversal of 114034422013 is 310224430411.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in 2 ways, for example, as 17072558244 + 96961863769 = 130662^2 + 311387^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2k-114034422013 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (114034422023) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 15865378 + ... + 15872563.

It is an arithmetic number, because the mean of its divisors is an integer number (28516540887).

Almost surely, 2114034422013 is an apocalyptic number.

It is an amenable number.

114034422013 is a deficient number, since it is larger than the sum of its proper divisors (31741535).

114034422013 is an equidigital number, since it uses as much as digits as its factorization.

114034422013 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 31741534.

The product of its (nonzero) digits is 2304, while the sum is 25.

Adding to 114034422013 its reverse (310224430411), we get a palindrome (424258852424).

The spelling of 114034422013 in words is "one hundred fourteen billion, thirty-four million, four hundred twenty-two thousand, thirteen".

Divisors: 1 3593 31737941 114034422013