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114034551013003 is a prime number
BaseRepresentation
bin11001111011011010111100…
…111001111011111010001011
3112221202121002221001210121111
4121323122330321323322023
5104421320230024404003
61042310425521551151
733006503323346215
oct3173327471737213
9487677087053544
10114034551013003
1133375866199265
12109587b04a54b7
134b82548289c8a
142023431cb35b5
15d2b478b0ee6d
hex67b6bce7be8b

114034551013003 has 2 divisors, whose sum is σ = 114034551013004. Its totient is φ = 114034551013002.

The previous prime is 114034551012997. The next prime is 114034551013069. The reversal of 114034551013003 is 300310155430411.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 114034551013003 - 237 = 113897112059531 is a prime.

It is not a weakly prime, because it can be changed into another prime (114034551083003) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (31) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57017275506501 + 57017275506502.

It is an arithmetic number, because the mean of its divisors is an integer number (57017275506502).

Almost surely, 2114034551013003 is an apocalyptic number.

114034551013003 is a deficient number, since it is larger than the sum of its proper divisors (1).

114034551013003 is an equidigital number, since it uses as much as digits as its factorization.

114034551013003 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 10800, while the sum is 31.

The spelling of 114034551013003 in words is "one hundred fourteen trillion, thirty-four billion, five hundred fifty-one million, thirteen thousand, three".