Base | Representation |
---|---|
bin | 1010010111110011001101… |
… | …1100010110100101011001 |
3 | 1111101012201110021011200101 |
4 | 2211330303130112211121 |
5 | 2443320343304211213 |
6 | 40130531552135401 |
7 | 2254624532111263 |
oct | 245746334264531 |
9 | 44335643234611 |
10 | 11404001241433 |
11 | 36a7456443209 |
12 | 1342208b37561 |
13 | 6495149c9b78 |
14 | 2b5d56cd2b33 |
15 | 14b99e4c0bdd |
hex | a5f33716959 |
11404001241433 has 2 divisors, whose sum is σ = 11404001241434. Its totient is φ = 11404001241432.
The previous prime is 11404001241371. The next prime is 11404001241443. The reversal of 11404001241433 is 33414210040411.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10056458700864 + 1347542540569 = 3171192^2 + 1160837^2 .
It is a cyclic number.
It is not a de Polignac number, because 11404001241433 - 29 = 11404001240921 is a prime.
It is not a weakly prime, because it can be changed into another prime (11404001241443) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5702000620716 + 5702000620717.
It is an arithmetic number, because the mean of its divisors is an integer number (5702000620717).
Almost surely, 211404001241433 is an apocalyptic number.
It is an amenable number.
11404001241433 is a deficient number, since it is larger than the sum of its proper divisors (1).
11404001241433 is an equidigital number, since it uses as much as digits as its factorization.
11404001241433 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 4608, while the sum is 28.
Adding to 11404001241433 its reverse (33414210040411), we get a palindrome (44818211281844).
The spelling of 11404001241433 in words is "eleven trillion, four hundred four billion, one million, two hundred forty-one thousand, four hundred thirty-three".
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