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11404006413 = 33801335471
BaseRepresentation
bin10101001111011101…
…10101010000001101
31002102202122112211220
422213232311100031
5141323411201123
65123335233553
7552413312052
oct124756652015
932382575756
1011404006413
11492229a898
1222632188b9
1310c983c6b7
147a27d9029
1546b294ce3
hex2a7bb540d

11404006413 has 4 divisors (see below), whose sum is σ = 15205341888. Its totient is φ = 7602670940.

The previous prime is 11404006391. The next prime is 11404006421. The reversal of 11404006413 is 31460040411.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is a cyclic number.

It is not a de Polignac number, because 11404006413 - 29 = 11404005901 is a prime.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11404006423) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1900667733 + ... + 1900667738.

It is an arithmetic number, because the mean of its divisors is an integer number (3801335472).

Almost surely, 211404006413 is an apocalyptic number.

It is an amenable number.

11404006413 is a deficient number, since it is larger than the sum of its proper divisors (3801335475).

11404006413 is an equidigital number, since it uses as much as digits as its factorization.

11404006413 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 3801335474.

The product of its (nonzero) digits is 1152, while the sum is 24.

Adding to 11404006413 its reverse (31460040411), we get a palindrome (42864046824).

The spelling of 11404006413 in words is "eleven billion, four hundred four million, six thousand, four hundred thirteen".

Divisors: 1 3 3801335471 11404006413