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114040415433 = 3723413227303
BaseRepresentation
bin110101000110101010…
…1101010010011001001
3101220100200011100101010
41222031111222103021
53332023321243213
6124220041514133
711145012352200
oct1521525522311
9356320140333
10114040415433
114440092901a
121a127aa2949
13a9a55cc279
14573ba58237
152e76ba2ac3
hex1a8d56a4c9

114040415433 has 24 divisors (see below), whose sum is σ = 176931615168. Its totient is φ = 65146571616.

The previous prime is 114040415381. The next prime is 114040415443. The reversal of 114040415433 is 334514040411.

It is not a de Polignac number, because 114040415433 - 217 = 114040284361 is a prime.

It is a self number, because there is not a number n which added to its sum of digits gives 114040415433.

It is not an unprimeable number, because it can be changed into a prime (114040415443) by changing a digit.

It is a polite number, since it can be written in 23 ways as a sum of consecutive naturals, for example, 388060 + ... + 615362.

It is an arithmetic number, because the mean of its divisors is an integer number (7372150632).

Almost surely, 2114040415433 is an apocalyptic number.

It is an amenable number.

114040415433 is a deficient number, since it is larger than the sum of its proper divisors (62891199735).

114040415433 is a wasteful number, since it uses less digits than its factorization.

114040415433 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 230733 (or 230726 counting only the distinct ones).

The product of its (nonzero) digits is 11520, while the sum is 30.

Adding to 114040415433 its reverse (334514040411), we get a palindrome (448554455844).

The spelling of 114040415433 in words is "one hundred fourteen billion, forty million, four hundred fifteen thousand, four hundred thirty-three".

Divisors: 1 3 7 21 49 147 3413 10239 23891 71673 167237 227303 501711 681909 1591121 4773363 11137847 33413541 775785139 2327355417 5430495973 16291487919 38013471811 114040415433