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114040445210267 is a prime number
BaseRepresentation
bin11001111011100000011100…
…001110100000111010011011
3112221210011022201001001012212
4121323200130032200322123
5104421414312433212032
61042313242435025335
733010102354243622
oct3173403416407233
9487704281031185
10114040445210267
1133378310324974
121095997643b24b
134b82c7745cc74
142023830a206b9
15d2b6c12e8bb2
hex67b81c3a0e9b

114040445210267 has 2 divisors, whose sum is σ = 114040445210268. Its totient is φ = 114040445210266.

The previous prime is 114040445210243. The next prime is 114040445210353. The reversal of 114040445210267 is 762012544040411.

It is a weak prime.

It is a cyclic number.

It is not a de Polignac number, because 114040445210267 - 218 = 114040444948123 is a prime.

It is a super-2 number, since 2×1140404452102672 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (114040495210267) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57020222605133 + 57020222605134.

It is an arithmetic number, because the mean of its divisors is an integer number (57020222605134).

Almost surely, 2114040445210267 is an apocalyptic number.

114040445210267 is a deficient number, since it is larger than the sum of its proper divisors (1).

114040445210267 is an equidigital number, since it uses as much as digits as its factorization.

114040445210267 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 215040, while the sum is 41.

Adding to 114040445210267 its reverse (762012544040411), we get a palindrome (876052989250678).

The spelling of 114040445210267 in words is "one hundred fourteen trillion, forty billion, four hundred forty-five million, two hundred ten thousand, two hundred sixty-seven".