Base | Representation |
---|---|
bin | 11001111011100000011100… |
… | …001110100000111010011011 |
3 | 112221210011022201001001012212 |
4 | 121323200130032200322123 |
5 | 104421414312433212032 |
6 | 1042313242435025335 |
7 | 33010102354243622 |
oct | 3173403416407233 |
9 | 487704281031185 |
10 | 114040445210267 |
11 | 33378310324974 |
12 | 1095997643b24b |
13 | 4b82c7745cc74 |
14 | 2023830a206b9 |
15 | d2b6c12e8bb2 |
hex | 67b81c3a0e9b |
114040445210267 has 2 divisors, whose sum is σ = 114040445210268. Its totient is φ = 114040445210266.
The previous prime is 114040445210243. The next prime is 114040445210353. The reversal of 114040445210267 is 762012544040411.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 114040445210267 - 218 = 114040444948123 is a prime.
It is a super-2 number, since 2×1140404452102672 (a number of 29 digits) contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (114040495210267) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57020222605133 + 57020222605134.
It is an arithmetic number, because the mean of its divisors is an integer number (57020222605134).
Almost surely, 2114040445210267 is an apocalyptic number.
114040445210267 is a deficient number, since it is larger than the sum of its proper divisors (1).
114040445210267 is an equidigital number, since it uses as much as digits as its factorization.
114040445210267 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 215040, while the sum is 41.
Adding to 114040445210267 its reverse (762012544040411), we get a palindrome (876052989250678).
The spelling of 114040445210267 in words is "one hundred fourteen trillion, forty billion, four hundred forty-five million, two hundred ten thousand, two hundred sixty-seven".
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