Base | Representation |
---|---|
bin | 1101100110000… |
… | …10000011011011 |
3 | 21221120212220122 |
4 | 12303002003123 |
5 | 213143303201 |
6 | 15152143455 |
7 | 2553222125 |
oct | 663020333 |
9 | 257525818 |
10 | 114041051 |
11 | 59411803 |
12 | 32237b8b |
13 | 1a81b817 |
14 | 11208215 |
15 | a029e1b |
hex | 6cc20db |
114041051 has 2 divisors, whose sum is σ = 114041052. Its totient is φ = 114041050.
The previous prime is 114041027. The next prime is 114041063. The reversal of 114041051 is 150140411.
It is a strong prime.
It is an emirp because it is prime and its reverse (150140411) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 114041051 - 26 = 114040987 is a prime.
It is a super-2 number, since 2×1140410512 = 26010722626369202, which contains 22 as substring.
It is not a weakly prime, because it can be changed into another prime (114041651) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (13) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57020525 + 57020526.
It is an arithmetic number, because the mean of its divisors is an integer number (57020526).
Almost surely, 2114041051 is an apocalyptic number.
114041051 is a deficient number, since it is larger than the sum of its proper divisors (1).
114041051 is an equidigital number, since it uses as much as digits as its factorization.
114041051 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 80, while the sum is 17.
The square root of 114041051 is about 10679.0004682086. Note that the first 3 decimals coincide. The cubic root of 114041051 is about 484.9389528860.
Adding to 114041051 its reverse (150140411), we get a palindrome (264181462).
The spelling of 114041051 in words is "one hundred fourteen million, forty-one thousand, fifty-one".
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