Base | Representation |
---|---|
bin | 10000100110000110100… |
… | …001110000110101000110 |
3 | 11001000122001200202101102 |
4 | 100212012201300311012 |
5 | 122141041333044032 |
6 | 2231523033500102 |
7 | 145251516241634 |
oct | 20460641606506 |
9 | 4030561622342 |
10 | 1140423331142 |
11 | 3aa71826aa87 |
12 | 165031571632 |
13 | 8370677a824 |
14 | 3d2a7d90354 |
15 | 1e9e9709362 |
hex | 10986870d46 |
1140423331142 has 4 divisors (see below), whose sum is σ = 1710634996716. Its totient is φ = 570211665570.
The previous prime is 1140423331133. The next prime is 1140423331199. The reversal of 1140423331142 is 2411333240411.
It is a semiprime because it is the product of two primes.
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 285105832784 + ... + 285105832787.
It is an arithmetic number, because the mean of its divisors is an integer number (427658749179).
Almost surely, 21140423331142 is an apocalyptic number.
1140423331142 is a deficient number, since it is larger than the sum of its proper divisors (570211665574).
1140423331142 is an equidigital number, since it uses as much as digits as its factorization.
1140423331142 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 570211665573.
The product of its (nonzero) digits is 6912, while the sum is 29.
Adding to 1140423331142 its reverse (2411333240411), we get a palindrome (3551756571553).
The spelling of 1140423331142 in words is "one trillion, one hundred forty billion, four hundred twenty-three million, three hundred thirty-one thousand, one hundred forty-two".
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