Search a number
-
+
114043413055042 = 257021706527521
BaseRepresentation
bin11001111011100011001101…
…000111111100011001000010
3112221210102222112120011212201
4121323203031013330121002
5104421441402220230132
61042314453134143414
733010236042433402
oct3173431507743102
9487712875504781
10114043413055042
11333795a3622649
121095a464351b6a
134b8332b296533
142023a32c56802
15d2b7e6b3a2e7
hex67b8cd1fc642

114043413055042 has 4 divisors (see below), whose sum is σ = 171065119582566. Its totient is φ = 57021706527520.

The previous prime is 114043413055021. The next prime is 114043413055097. The reversal of 114043413055042 is 240550314340411.

It is a happy number.

It is a semiprime because it is the product of two primes.

It can be written as a sum of positive squares in only one way, i.e., 57705763937761 + 56337649117281 = 7596431^2 + 7505841^2 .

It is a super-2 number, since 2×1140434130550422 (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 114043413054992 and 114043413055010.

It is an unprimeable number.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28510853263759 + ... + 28510853263762.

Almost surely, 2114043413055042 is an apocalyptic number.

114043413055042 is a deficient number, since it is larger than the sum of its proper divisors (57021706527524).

114043413055042 is an equidigital number, since it uses as much as digits as its factorization.

114043413055042 is an odious number, because the sum of its binary digits is odd.

The sum of its prime factors is 57021706527523.

The product of its (nonzero) digits is 115200, while the sum is 37.

Adding to 114043413055042 its reverse (240550314340411), we get a palindrome (354593727395453).

The spelling of 114043413055042 in words is "one hundred fourteen trillion, forty-three billion, four hundred thirteen million, fifty-five thousand, forty-two".

Divisors: 1 2 57021706527521 114043413055042