Base | Representation |
---|---|
bin | 11001111011100011001101… |
… | …000111111100011001000010 |
3 | 112221210102222112120011212201 |
4 | 121323203031013330121002 |
5 | 104421441402220230132 |
6 | 1042314453134143414 |
7 | 33010236042433402 |
oct | 3173431507743102 |
9 | 487712875504781 |
10 | 114043413055042 |
11 | 333795a3622649 |
12 | 1095a464351b6a |
13 | 4b8332b296533 |
14 | 2023a32c56802 |
15 | d2b7e6b3a2e7 |
hex | 67b8cd1fc642 |
114043413055042 has 4 divisors (see below), whose sum is σ = 171065119582566. Its totient is φ = 57021706527520.
The previous prime is 114043413055021. The next prime is 114043413055097. The reversal of 114043413055042 is 240550314340411.
It is a happy number.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in only one way, i.e., 57705763937761 + 56337649117281 = 7596431^2 + 7505841^2 .
It is a super-2 number, since 2×1140434130550422 (a number of 29 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 114043413054992 and 114043413055010.
It is an unprimeable number.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 28510853263759 + ... + 28510853263762.
Almost surely, 2114043413055042 is an apocalyptic number.
114043413055042 is a deficient number, since it is larger than the sum of its proper divisors (57021706527524).
114043413055042 is an equidigital number, since it uses as much as digits as its factorization.
114043413055042 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 57021706527523.
The product of its (nonzero) digits is 115200, while the sum is 37.
Adding to 114043413055042 its reverse (240550314340411), we get a palindrome (354593727395453).
The spelling of 114043413055042 in words is "one hundred fourteen trillion, forty-three billion, four hundred thirteen million, fifty-five thousand, forty-two".
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