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11404433333 = 13128321087
BaseRepresentation
bin10101001111100000…
…11101011110110101
31002102210110020110202
422213300131132311
5141324013331313
65123352330245
7552420040526
oct124760353665
932383406422
1011404433333
114922561617
1222633a3985
1310c995bb07
147a28aa84d
1546b32b558
hex2a7c1d7b5

11404433333 has 12 divisors (see below), whose sum is σ = 11542848768. Its totient is φ = 11267011080.

The previous prime is 11404433279. The next prime is 11404433363. The reversal of 11404433333 is 33333440411.

It is not a de Polignac number, because 11404433333 - 212 = 11404429237 is a prime.

It is a super-2 number, since 2×114044333332 (a number of 21 digits) contains 22 as substring.

It is a Duffinian number.

It is a junction number, because it is equal to n+sod(n) for n = 11404433296 and 11404433305.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (11404433363) by changing a digit.

It is a polite number, since it can be written in 11 ways as a sum of consecutive naturals, for example, 10491116 + ... + 10492202.

It is an arithmetic number, because the mean of its divisors is an integer number (961904064).

Almost surely, 211404433333 is an apocalyptic number.

It is an amenable number.

11404433333 is a deficient number, since it is larger than the sum of its proper divisors (138415435).

11404433333 is an equidigital number, since it uses as much as digits as its factorization.

11404433333 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 1784 (or 1501 counting only the distinct ones).

The product of its (nonzero) digits is 15552, while the sum is 29.

Adding to 11404433333 its reverse (33333440411), we get a palindrome (44737873744).

The spelling of 11404433333 in words is "eleven billion, four hundred four million, four hundred thirty-three thousand, three hundred thirty-three".

Divisors: 1 131 283 1087 37073 80089 142397 307621 10491659 40298351 87056743 11404433333