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114050253697 is a prime number
BaseRepresentation
bin110101000110111101…
…1001100001110000001
3101220101100200011221021
41222031323030032001
53332033331104242
6124221032425441
711145162106162
oct1521573141601
9356340604837
10114050253697
1144406438716
121a12b248281
13a9a7665323
14573d099769
152e77997b67
hex1a8decc381

114050253697 has 2 divisors, whose sum is σ = 114050253698. Its totient is φ = 114050253696.

The previous prime is 114050253679. The next prime is 114050253743. The reversal of 114050253697 is 796352050411.

Together with previous prime (114050253679) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 65681488656 + 48368765041 = 256284^2 + 219929^2 .

It is a cyclic number.

It is not a de Polignac number, because 114050253697 - 223 = 114041865089 is a prime.

It is not a weakly prime, because it can be changed into another prime (114050253607) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57025126848 + 57025126849.

It is an arithmetic number, because the mean of its divisors is an integer number (57025126849).

Almost surely, 2114050253697 is an apocalyptic number.

It is an amenable number.

114050253697 is a deficient number, since it is larger than the sum of its proper divisors (1).

114050253697 is an equidigital number, since it uses as much as digits as its factorization.

114050253697 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 226800, while the sum is 43.

The spelling of 114050253697 in words is "one hundred fourteen billion, fifty million, two hundred fifty-three thousand, six hundred ninety-seven".