Base | Representation |
---|---|
bin | 10101001111100110… |
… | …00010110100010111 |
3 | 1002102211201122102220 |
4 | 22213303002310113 |
5 | 141324202014201 |
6 | 5123415033423 |
7 | 552425561112 |
oct | 124763026427 |
9 | 32384648386 |
10 | 11405110551 |
11 | 49229843aa |
12 | 226366b873 |
13 | 10c9b38133 |
14 | 7a2a05579 |
15 | 46b412036 |
hex | 2a7cc2d17 |
11405110551 has 4 divisors (see below), whose sum is σ = 15206814072. Its totient is φ = 7603407032.
The previous prime is 11405110537. The next prime is 11405110553. The reversal of 11405110551 is 15501150411.
It is a semiprime because it is the product of two primes, and also an emirpimes, since its reverse is a distinct semiprime: 15501150411 = 3 ⋅5167050137.
It is a cyclic number.
It is not a de Polignac number, because 11405110551 - 211 = 11405108503 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11405110553) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 1900851756 + ... + 1900851761.
It is an arithmetic number, because the mean of its divisors is an integer number (3801703518).
Almost surely, 211405110551 is an apocalyptic number.
11405110551 is a deficient number, since it is larger than the sum of its proper divisors (3801703521).
11405110551 is an equidigital number, since it uses as much as digits as its factorization.
11405110551 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 3801703520.
The product of its (nonzero) digits is 500, while the sum is 24.
Adding to 11405110551 its reverse (15501150411), we get a palindrome (26906260962).
The spelling of 11405110551 in words is "eleven billion, four hundred five million, one hundred ten thousand, five hundred fifty-one".
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