Base | Representation |
---|---|
bin | 10101001111100111… |
… | …10100000000110111 |
3 | 1002102212002212212000 |
4 | 22213303310000313 |
5 | 141324224441210 |
6 | 5123423230343 |
7 | 552430360434 |
oct | 124763640067 |
9 | 32385085760 |
10 | 11405312055 |
11 | 4923001835 |
12 | 22637483b3 |
13 | 10c9ba8a77 |
14 | 7a2a58b8b |
15 | 46b451ac0 |
hex | 2a7cf4037 |
11405312055 has 32 divisors (see below), whose sum is σ = 20472990720. Its totient is φ = 6023769120.
The previous prime is 11405312047. The next prime is 11405312159. The reversal of 11405312055 is 55021350411.
It is not a de Polignac number, because 11405312055 - 23 = 11405312047 is a prime.
It is a super-2 number, since 2×114053120552 (a number of 21 digits) contains 22 as substring.
It is a Harshad number since it is a multiple of its sum of digits (27).
It is a congruent number.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 396211 + ... + 424020.
It is an arithmetic number, because the mean of its divisors is an integer number (639780960).
Almost surely, 211405312055 is an apocalyptic number.
11405312055 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
11405312055 is a deficient number, since it is larger than the sum of its proper divisors (9067678665).
11405312055 is a wasteful number, since it uses less digits than its factorization.
11405312055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 820348 (or 820342 counting only the distinct ones).
The product of its (nonzero) digits is 3000, while the sum is 27.
Adding to 11405312055 its reverse (55021350411), we get a palindrome (66426662466).
The spelling of 11405312055 in words is "eleven billion, four hundred five million, three hundred twelve thousand, fifty-five".
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