Base | Representation |
---|---|
bin | 10101001111101000… |
… | …10000111100011011 |
3 | 1002102212022220101220 |
4 | 22213310100330123 |
5 | 141324242234210 |
6 | 5123425543123 |
7 | 552431363061 |
oct | 124764207433 |
9 | 32385286356 |
10 | 11405430555 |
11 | 4923082872 |
12 | 22637a4aa3 |
13 | 10c9c1a99c |
14 | 7a2a8a031 |
15 | 46b476c70 |
hex | 2a7d10f1b |
11405430555 has 32 divisors (see below), whose sum is σ = 19230704640. Its totient is φ = 5760796800.
The previous prime is 11405430541. The next prime is 11405430571. The reversal of 11405430555 is 55503450411.
It is not a de Polignac number, because 11405430555 - 27 = 11405430427 is a prime.
It is a super-2 number, since 2×114054305552 (a number of 21 digits) contains 22 as substring.
It is an unprimeable number.
It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 128815 + ... + 198504.
It is an arithmetic number, because the mean of its divisors is an integer number (600959520).
Almost surely, 211405430555 is an apocalyptic number.
11405430555 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
11405430555 is a deficient number, since it is larger than the sum of its proper divisors (7825274085).
11405430555 is a wasteful number, since it uses less digits than its factorization.
11405430555 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 327451.
The product of its (nonzero) digits is 30000, while the sum is 33.
Adding to 11405430555 its reverse (55503450411), we get a palindrome (66908880966).
The spelling of 11405430555 in words is "eleven billion, four hundred five million, four hundred thirty thousand, five hundred fifty-five".
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