Base | Representation |
---|---|
bin | 10101001111110111… |
… | …11001110110110111 |
3 | 1002110000002122102211 |
4 | 22213323321312313 |
5 | 141330300330033 |
6 | 5123540514251 |
7 | 552454403401 |
oct | 124773716667 |
9 | 32400078384 |
10 | 11407433143 |
11 | 49242203a7 |
12 | 22643ab987 |
13 | 10ca46c352 |
14 | 7a304bb71 |
15 | 46b7202cd |
hex | 2a7ef9db7 |
11407433143 has 6 divisors (see below), whose sum is σ = 12117931016. Its totient is φ = 10736407392.
The previous prime is 11407433137. The next prime is 11407433159. The reversal of 11407433143 is 34133470411.
It is a de Polignac number, because none of the positive numbers 2k-11407433143 is a prime.
It is a super-3 number, since 3×114074331433 (a number of 31 digits) contains 333 as substring.
It is a Duffinian number.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (11407433173) by changing a digit.
It is a polite number, since it can be written in 5 ways as a sum of consecutive naturals, for example, 19735755 + ... + 19736332.
Almost surely, 211407433143 is an apocalyptic number.
11407433143 is a deficient number, since it is larger than the sum of its proper divisors (710497873).
11407433143 is an equidigital number, since it uses as much as digits as its factorization.
11407433143 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 39472121 (or 39472104 counting only the distinct ones).
The product of its (nonzero) digits is 12096, while the sum is 31.
The spelling of 11407433143 in words is "eleven billion, four hundred seven million, four hundred thirty-three thousand, one hundred forty-three".
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