1140750831401 has 2 divisors, whose sum is σ = 1140750831402. Its totient is φ = 1140750831400.

The previous prime is 1140750831383. The next prime is 1140750831481. The reversal of 1140750831401 is 1041380570411.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 914863555225 + 225887276176 = 956485^2 + 475276^2 .

It is a cyclic number.

It is a de Polignac number, because none of the positive numbers 2^k-1140750831401 is a prime.

It is not a weakly prime, because it can be changed into another prime (1140750831481) by changing a digit.

It is a pernicious number, because its binary representation contains a prime number (17) of ones.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570375415700 + 570375415701.

It is an arithmetic number, because the mean of its divisors is an integer number (570375415701).

Almost surely, 2^{1140750831401} is an apocalyptic number.

It is an amenable number.

1140750831401 is a deficient number, since it is larger than the sum of its proper divisors (1).

1140750831401 is an equidigital number, since it uses as much as digits as its factorization.

1140750831401 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 13440, while the sum is 35.

The spelling of 1140750831401 in words is "one trillion, one hundred forty billion, seven hundred fifty million, eight hundred thirty-one thousand, four hundred one".