Base | Representation |
---|---|
bin | 110101001000011101… |
… | …0101000110000111001 |
3 | 101220111212002220202201 |
4 | 1222100322220300321 |
5 | 3332134203040441 |
6 | 124230024230201 |
7 | 11146341511243 |
oct | 1522072506071 |
9 | 356455086681 |
10 | 114100440121 |
11 | 444317a64a8 |
12 | 1a14400b361 |
13 | a9b4b87535 |
14 | 5745a01093 |
15 | 2e7c0acc31 |
hex | 1a90ea8c39 |
114100440121 has 2 divisors, whose sum is σ = 114100440122. Its totient is φ = 114100440120.
The previous prime is 114100440107. The next prime is 114100440143. The reversal of 114100440121 is 121044001411.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 106057040896 + 8043399225 = 325664^2 + 89685^2 .
It is a cyclic number.
It is not a de Polignac number, because 114100440121 - 215 = 114100407353 is a prime.
It is not a weakly prime, because it can be changed into another prime (114100444121) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57050220060 + 57050220061.
It is an arithmetic number, because the mean of its divisors is an integer number (57050220061).
Almost surely, 2114100440121 is an apocalyptic number.
It is an amenable number.
114100440121 is a deficient number, since it is larger than the sum of its proper divisors (1).
114100440121 is an equidigital number, since it uses as much as digits as its factorization.
114100440121 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 128, while the sum is 19.
Adding to 114100440121 its reverse (121044001411), we get a palindrome (235144441532).
The spelling of 114100440121 in words is "one hundred fourteen billion, one hundred million, four hundred forty thousand, one hundred twenty-one".
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