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1141005327793 is a prime number
BaseRepresentation
bin10000100110101001001…
…101111001110110110001
311001002010121211020200221
4100212221031321312301
5122143234330442133
62232100504013041
7145302114156112
oct20465115716661
94032117736627
101141005327793
113aa996841751
12165174461181
138379a211a46
143d3213ac209
151ea3086ca2d
hex109a9379db1

1141005327793 has 2 divisors, whose sum is σ = 1141005327794. Its totient is φ = 1141005327792.

The previous prime is 1141005327697. The next prime is 1141005327809. The reversal of 1141005327793 is 3977235001411.

It is a strong prime.

It can be written as a sum of positive squares in only one way, i.e., 678947984289 + 462057343504 = 823983^2 + 679748^2 .

It is a cyclic number.

It is not a de Polignac number, because 1141005327793 - 221 = 1141003230641 is a prime.

It is a super-2 number, since 2×11410053277932 (a number of 25 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (1141005325793) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570502663896 + 570502663897.

It is an arithmetic number, because the mean of its divisors is an integer number (570502663897).

Almost surely, 21141005327793 is an apocalyptic number.

It is an amenable number.

1141005327793 is a deficient number, since it is larger than the sum of its proper divisors (1).

1141005327793 is an equidigital number, since it uses as much as digits as its factorization.

1141005327793 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 158760, while the sum is 43.

The spelling of 1141005327793 in words is "one trillion, one hundred forty-one billion, five million, three hundred twenty-seven thousand, seven hundred ninety-three".