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114101314665467 is a prime number
BaseRepresentation
bin11001111100011001001000…
…010101000011101111111011
3112221222222102210122202021112
4121330121020111003233323
5104423413443023243332
61042401230442430535
733014355642132263
oct3174311025035773
9487888383582245
10114101314665467
11333a1106571548
121096972350244b
134b8892807a88c
142026766b5c7a3
15d2d085042db2
hex67c648543bfb

114101314665467 has 2 divisors, whose sum is σ = 114101314665468. Its totient is φ = 114101314665466.

The previous prime is 114101314665461. The next prime is 114101314665607. The reversal of 114101314665467 is 764566413101411.

It is a weak prime.

It is an emirp because it is prime and its reverse (764566413101411) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 114101314665467 - 224 = 114101297888251 is a prime.

It is a super-2 number, since 2×1141013146654672 (a number of 29 digits) contains 22 as substring.

It is not a weakly prime, because it can be changed into another prime (114101314665461) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57050657332733 + 57050657332734.

It is an arithmetic number, because the mean of its divisors is an integer number (57050657332734).

Almost surely, 2114101314665467 is an apocalyptic number.

114101314665467 is a deficient number, since it is larger than the sum of its proper divisors (1).

114101314665467 is an equidigital number, since it uses as much as digits as its factorization.

114101314665467 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 1451520, while the sum is 50.

Adding to 114101314665467 its reverse (764566413101411), we get a palindrome (878667727766878).

The spelling of 114101314665467 in words is "one hundred fourteen trillion, one hundred one billion, three hundred fourteen million, six hundred sixty-five thousand, four hundred sixty-seven".