Base | Representation |
---|---|
bin | 110101001000100010… |
… | …0110101010110100001 |
3 | 101220112001010201102201 |
4 | 1222101010311112201 |
5 | 3332140344104441 |
6 | 124230201413201 |
7 | 11146403313244 |
oct | 1522104652641 |
9 | 356461121381 |
10 | 114103113121 |
11 | 44433261798 |
12 | 1a144a9a201 |
13 | a9b55b20aa |
14 | 57460d925b |
15 | 2e7c439c31 |
hex | 1a911355a1 |
114103113121 has 2 divisors, whose sum is σ = 114103113122. Its totient is φ = 114103113120.
The previous prime is 114103113109. The next prime is 114103113203. The reversal of 114103113121 is 121311301411.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 57190331025 + 56912782096 = 239145^2 + 238564^2 .
It is an emirp because it is prime and its reverse (121311301411) is a distict prime.
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-114103113121 is a prime.
It is not a weakly prime, because it can be changed into another prime (114103113101) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57051556560 + 57051556561.
It is an arithmetic number, because the mean of its divisors is an integer number (57051556561).
Almost surely, 2114103113121 is an apocalyptic number.
It is an amenable number.
114103113121 is a deficient number, since it is larger than the sum of its proper divisors (1).
114103113121 is an equidigital number, since it uses as much as digits as its factorization.
114103113121 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 72, while the sum is 19.
Adding to 114103113121 its reverse (121311301411), we get a palindrome (235414414532).
The spelling of 114103113121 in words is "one hundred fourteen billion, one hundred three million, one hundred thirteen thousand, one hundred twenty-one".
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