114103315514033 has 2 divisors, whose sum is σ = 114103315514034. Its totient is φ = 114103315514032.

The previous prime is 114103315514009. The next prime is 114103315514059. The reversal of 114103315514033 is 330415513301411.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 82861386569329 + 31241928944704 = 9102823^2 + 5589448^2 .

It is a cyclic number.

It is not a de Polignac number, because 114103315514033 - 2¹⁰ = 114103315513009 is a prime.

It is a super-2 number, since 2×114103315514033² (a number of 29 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 114103315513984 and 114103315514002.

It is not a weakly prime, because it can be changed into another prime (114103315514003) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57051657757016 + 57051657757017.

It is an arithmetic number, because the mean of its divisors is an integer number (57051657757017).

Almost surely, 2^{114103315514033} is an apocalyptic number.

It is an amenable number.

114103315514033 is a deficient number, since it is larger than the sum of its proper divisors (1).

114103315514033 is an equidigital number, since it uses as much as digits as its factorization.

114103315514033 is an odious number, because the sum of its binary digits is odd.

The product of its (nonzero) digits is 32400, while the sum is 35.

Adding to 114103315514033 its reverse (330415513301411), we get a palindrome (444518828815444).

The spelling of 114103315514033 in words is "one hundred fourteen trillion, one hundred three billion, three hundred fifteen million, five hundred fourteen thousand, thirty-three".