Base | Representation |
---|---|
bin | 10101010000001101… |
… | …11101111000010001 |
3 | 1002110012112222120101 |
4 | 22220012331320101 |
5 | 141332021130301 |
6 | 5124123012401 |
7 | 552521142361 |
oct | 125006757021 |
9 | 32405488511 |
10 | 11410333201 |
11 | 4925921243 |
12 | 226536a101 |
13 | 10cac46367 |
14 | 7a35a49a1 |
15 | 46bae4701 |
hex | 2a81bde11 |
11410333201 has 2 divisors, whose sum is σ = 11410333202. Its totient is φ = 11410333200.
The previous prime is 11410333183. The next prime is 11410333217. The reversal of 11410333201 is 10233301411.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 10160640000 + 1249693201 = 100800^2 + 35351^2 .
It is an emirp because it is prime and its reverse (10233301411) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 11410333201 - 217 = 11410202129 is a prime.
It is not a weakly prime, because it can be changed into another prime (11410333901) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5705166600 + 5705166601.
It is an arithmetic number, because the mean of its divisors is an integer number (5705166601).
Almost surely, 211410333201 is an apocalyptic number.
It is an amenable number.
11410333201 is a deficient number, since it is larger than the sum of its proper divisors (1).
11410333201 is an equidigital number, since it uses as much as digits as its factorization.
11410333201 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 216, while the sum is 19.
Adding to 11410333201 its reverse (10233301411), we get a palindrome (21643634612).
The spelling of 11410333201 in words is "eleven billion, four hundred ten million, three hundred thirty-three thousand, two hundred one".
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