Base | Representation |
---|---|
bin | 10000100110101011011… |
… | …110011100111001100011 |
3 | 11001002020021010101010111 |
4 | 100212223132130321203 |
5 | 122143324031020232 |
6 | 2232104340112151 |
7 | 145303054225162 |
oct | 20465336347143 |
9 | 4032207111114 |
10 | 1141043220067 |
11 | 3aaa06172783 |
12 | 165185095657 |
13 | 837a501b0ca |
14 | 3d3264333d9 |
15 | 1ea33d55047 |
hex | 109ab79ce63 |
1141043220067 has 2 divisors, whose sum is σ = 1141043220068. Its totient is φ = 1141043220066.
The previous prime is 1141043220001. The next prime is 1141043220131. The reversal of 1141043220067 is 7600223401411.
It is a strong prime.
It is a cyclic number.
It is not a de Polignac number, because 1141043220067 - 215 = 1141043187299 is a prime.
It is not a weakly prime, because it can be changed into another prime (1141043280067) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570521610033 + 570521610034.
It is an arithmetic number, because the mean of its divisors is an integer number (570521610034).
Almost surely, 21141043220067 is an apocalyptic number.
1141043220067 is a deficient number, since it is larger than the sum of its proper divisors (1).
1141043220067 is an equidigital number, since it uses as much as digits as its factorization.
1141043220067 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 8064, while the sum is 31.
Adding to 1141043220067 its reverse (7600223401411), we get a palindrome (8741266621478).
The spelling of 1141043220067 in words is "one trillion, one hundred forty-one billion, forty-three million, two hundred twenty thousand, sixty-seven".
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