Base | Representation |
---|---|
bin | 11001111100011100100100… |
… | …110010011011111001000111 |
3 | 112222000022222120101121011202 |
4 | 121330130210302123321013 |
5 | 104423444031404312210 |
6 | 1042403041450253115 |
7 | 33014546413355033 |
oct | 3174344462337107 |
9 | 488008876347152 |
10 | 114105013354055 |
11 | 333a2734365a79 |
12 | 1096a39612719b |
13 | 4b890974325c9 |
14 | 20269d807b1c3 |
15 | d2d1eeaea9a5 |
hex | 67c724c9be47 |
114105013354055 has 16 divisors (see below), whose sum is σ = 137254260326400. Its totient is φ = 91065185761440.
The previous prime is 114105013354051. The next prime is 114105013354061. The reversal of 114105013354055 is 550453310501411.
It is not a de Polignac number, because 114105013354055 - 22 = 114105013354051 is a prime.
It is a congruent number.
It is not an unprimeable number, because it can be changed into a prime (114105013354051) by changing a digit.
It is a polite number, since it can be written in 15 ways as a sum of consecutive naturals, for example, 249476666 + ... + 249933624.
It is an arithmetic number, because the mean of its divisors is an integer number (8578391270400).
Almost surely, 2114105013354055 is an apocalyptic number.
114105013354055 is a deficient number, since it is larger than the sum of its proper divisors (23149246972345).
114105013354055 is a wasteful number, since it uses less digits than its factorization.
114105013354055 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 576574.
The product of its (nonzero) digits is 90000, while the sum is 38.
Adding to 114105013354055 its reverse (550453310501411), we get a palindrome (664558323855466).
The spelling of 114105013354055 in words is "one hundred fourteen trillion, one hundred five billion, thirteen million, three hundred fifty-four thousand, fifty-five".
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