Base | Representation |
---|---|
bin | 11001111100011101000011… |
… | …000000101010111111110001 |
3 | 112222000101021220111022202201 |
4 | 121330131003000222333301 |
5 | 104424001101210334132 |
6 | 1042403204042143201 |
7 | 33014565111246115 |
oct | 3174350300527761 |
9 | 488011256438681 |
10 | 114105520402417 |
11 | 333a29745a6a05 |
12 | 1096a4b7ab1b01 |
13 | 4b891484b491b |
14 | 2026a45549745 |
15 | d2d22e3a72e7 |
hex | 67c74302aff1 |
114105520402417 has 2 divisors, whose sum is σ = 114105520402418. Its totient is φ = 114105520402416.
The previous prime is 114105520402381. The next prime is 114105520402421. The reversal of 114105520402417 is 714204025501411.
It is a strong prime.
It can be written as a sum of positive squares in only one way, i.e., 96138103440016 + 17967416962401 = 9805004^2 + 4238799^2 .
It is a cyclic number.
It is not a de Polignac number, because 114105520402417 - 215 = 114105520369649 is a prime.
It is not a weakly prime, because it can be changed into another prime (114105520402457) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57052760201208 + 57052760201209.
It is an arithmetic number, because the mean of its divisors is an integer number (57052760201209).
Almost surely, 2114105520402417 is an apocalyptic number.
It is an amenable number.
114105520402417 is a deficient number, since it is larger than the sum of its proper divisors (1).
114105520402417 is an equidigital number, since it uses as much as digits as its factorization.
114105520402417 is an odious number, because the sum of its binary digits is odd.
The product of its (nonzero) digits is 44800, while the sum is 37.
Adding to 114105520402417 its reverse (714204025501411), we get a palindrome (828309545903828).
The spelling of 114105520402417 in words is "one hundred fourteen trillion, one hundred five billion, five hundred twenty million, four hundred two thousand, four hundred seventeen".
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