1141113033131 has 2 divisors, whose sum is σ = 1141113033132. Its totient is φ = 1141113033130.

The previous prime is 1141113033113. The next prime is 1141113033223. The reversal of 1141113033131 is 1313303111411.

Together with previous prime (1141113033113) it forms an Ormiston pair, because they use the same digits, order apart.

It is a weak prime.

It is an emirp because it is prime and its reverse (1313303111411) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1141113033131 - 2³⁸ = 866235126187 is a prime.

It is a super-2 number, since 2×1141113033131² (a number of 25 digits) contains 22 as substring.

It is a junction number, because it is equal to n+sod(n) for n = 1141113033097 and 1141113033106.

It is not a weakly prime, because it can be changed into another prime (1141113033031) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570556516565 + 570556516566.

It is an arithmetic number, because the mean of its divisors is an integer number (570556516566).

Almost surely, 2^{1141113033131} is an apocalyptic number.

1141113033131 is a deficient number, since it is larger than the sum of its proper divisors (1).

1141113033131 is an equidigital number, since it uses as much as digits as its factorization.

1141113033131 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 324, while the sum is 23.

Adding to 1141113033131 its reverse (1313303111411), we get a palindrome (2454416144542).

The spelling of 1141113033131 in words is "one trillion, one hundred forty-one billion, one hundred thirteen million, thirty-three thousand, one hundred thirty-one".