1141113121033 has 2 divisors, whose sum is σ = 1141113121034. Its totient is φ = 1141113121032.

The previous prime is 1141113121009. The next prime is 1141113121069. The reversal of 1141113121033 is 3301213111411.

It is a weak prime.

It can be written as a sum of positive squares in only one way, i.e., 804657438729 + 336455682304 = 897027^2 + 580048^2 .

It is an emirp because it is prime and its reverse (3301213111411) is a distict prime.

It is a cyclic number.

It is not a de Polignac number, because 1141113121033 - 2³³ = 1132523186441 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1141113120995 and 1141113121013.

It is not a weakly prime, because it can be changed into another prime (1141113121433) by changing a digit.

It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570556560516 + 570556560517.

It is an arithmetic number, because the mean of its divisors is an integer number (570556560517).

Almost surely, 2^{1141113121033} is an apocalyptic number.

It is an amenable number.

1141113121033 is a deficient number, since it is larger than the sum of its proper divisors (1).

1141113121033 is an equidigital number, since it uses as much as digits as its factorization.

1141113121033 is an evil number, because the sum of its binary digits is even.

The product of its (nonzero) digits is 216, while the sum is 22.

Adding to 1141113121033 its reverse (3301213111411), we get a palindrome (4442326232444).

The spelling of 1141113121033 in words is "one trillion, one hundred forty-one billion, one hundred thirteen million, one hundred twenty-one thousand, thirty-three".