1141113121041 has 4 divisors (see below), whose sum is σ = 1521484161392. Its totient is φ = 760742080692.

The previous prime is 1141113121033. The next prime is 1141113121069. The reversal of 1141113121041 is 1401213111411.

It is a semiprime because it is the product of two primes, and also a Blum integer, because the two primes are equal to 3 mod 4.

It is not a de Polignac number, because 1141113121041 - 2³ = 1141113121033 is a prime.

It is a Duffinian number.

It is a Curzon number.

It is a junction number, because it is equal to n+sod(n) for n = 1141113120999 and 1141113121017.

It is not an unprimeable number, because it can be changed into a prime (1141113101041) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 190185520171 + ... + 190185520176.

It is an arithmetic number, because the mean of its divisors is an integer number (380371040348).

Almost surely, 2^{1141113121041} is an apocalyptic number.

It is an amenable number.

1141113121041 is a deficient number, since it is larger than the sum of its proper divisors (380371040351).

1141113121041 is an equidigital number, since it uses as much as digits as its factorization.

1141113121041 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 380371040350.

The product of its (nonzero) digits is 96, while the sum is 21.

Adding to 1141113121041 its reverse (1401213111411), we get a palindrome (2542326232452).

The spelling of 1141113121041 in words is "one trillion, one hundred forty-one billion, one hundred thirteen million, one hundred twenty-one thousand, forty-one".