Base | Representation |
---|---|
bin | 10000100110110000110… |
… | …001100101010101000011 |
3 | 11001002110110102000211212 |
4 | 100212300301211111003 |
5 | 122144014310341121 |
6 | 2232121233400335 |
7 | 145305213663602 |
oct | 20466061452503 |
9 | 4032413360755 |
10 | 1141132121411 |
11 | 3aaa51373667 |
12 | 1651aaa090ab |
13 | 837ba576c59 |
14 | 3d334175a39 |
15 | 1ea3ba6625b |
hex | 109b0c65543 |
1141132121411 has 2 divisors, whose sum is σ = 1141132121412. Its totient is φ = 1141132121410.
The previous prime is 1141132121359. The next prime is 1141132121429. The reversal of 1141132121411 is 1141212311411.
It is a strong prime.
It is an emirp because it is prime and its reverse (1141212311411) is a distict prime.
It is a cyclic number.
It is not a de Polignac number, because 1141132121411 - 238 = 866254214467 is a prime.
It is not a weakly prime, because it can be changed into another prime (1141132121431) by changing a digit.
It is a pernicious number, because its binary representation contains a prime number (17) of ones.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 570566060705 + 570566060706.
It is an arithmetic number, because the mean of its divisors is an integer number (570566060706).
Almost surely, 21141132121411 is an apocalyptic number.
1141132121411 is a deficient number, since it is larger than the sum of its proper divisors (1).
1141132121411 is an equidigital number, since it uses as much as digits as its factorization.
1141132121411 is an odious number, because the sum of its binary digits is odd.
The product of its digits is 192, while the sum is 23.
Adding to 1141132121411 its reverse (1141212311411), we get a palindrome (2282344432822).
The spelling of 1141132121411 in words is "one trillion, one hundred forty-one billion, one hundred thirty-two million, one hundred twenty-one thousand, four hundred eleven".
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