Base | Representation |
---|---|
bin | 110101001000111011… |
… | …1011000110000010111 |
3 | 101220112222002000001110 |
4 | 1222101313120300113 |
5 | 3332202242142320 |
6 | 124231353430103 |
7 | 11146624046400 |
oct | 1522167306027 |
9 | 356488060043 |
10 | 114116365335 |
11 | 4443a793335 |
12 | 1a14940b333 |
13 | a9b827203b |
14 | 5747b889a7 |
15 | 2e7d6a65e0 |
hex | 1a91dd8c17 |
114116365335 has 48 divisors (see below), whose sum is σ = 212572934496. Its totient is φ = 52124067072.
The previous prime is 114116365247. The next prime is 114116365351. The reversal of 114116365335 is 533563611411.
It is not a de Polignac number, because 114116365335 - 213 = 114116357143 is a prime.
It is a junction number, because it is equal to n+sod(n) for n = 114116365293 and 114116365302.
It is a congruent number.
It is an unprimeable number.
It is a pernicious number, because its binary representation contains a prime number (19) of ones.
It is a polite number, since it can be written in 47 ways as a sum of consecutive naturals, for example, 827557 + ... + 955553.
It is an arithmetic number, because the mean of its divisors is an integer number (4428602802).
Almost surely, 2114116365335 is an apocalyptic number.
114116365335 is a gapful number since it is divisible by the number (15) formed by its first and last digit.
114116365335 is a deficient number, since it is larger than the sum of its proper divisors (98456569161).
114116365335 is a wasteful number, since it uses less digits than its factorization.
114116365335 is an odious number, because the sum of its binary digits is odd.
The sum of its prime factors is 129232 (or 129225 counting only the distinct ones).
The product of its digits is 97200, while the sum is 39.
Adding to 114116365335 its reverse (533563611411), we get a palindrome (647679976746).
The spelling of 114116365335 in words is "one hundred fourteen billion, one hundred sixteen million, three hundred sixty-five thousand, three hundred thirty-five".
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