Base | Representation |
---|---|
bin | 110101001000111111… |
… | …1101111000000101001 |
3 | 101220120010012011211211 |
4 | 1222101333233000221 |
5 | 3332203322204031 |
6 | 124231512353121 |
7 | 11146651462321 |
oct | 1522177570051 |
9 | 356503164754 |
10 | 114118553641 |
11 | 44440a48454 |
12 | 1a14a0a57a1 |
13 | a9b885a0b1 |
14 | 5748198281 |
15 | 2e7d989bb1 |
hex | 1a91fef029 |
114118553641 has 2 divisors, whose sum is σ = 114118553642. Its totient is φ = 114118553640.
The previous prime is 114118553609. The next prime is 114118553701. The reversal of 114118553641 is 146355811411.
It is a weak prime.
It can be written as a sum of positive squares in only one way, i.e., 103359678016 + 10758875625 = 321496^2 + 103725^2 .
It is a cyclic number.
It is not a de Polignac number, because 114118553641 - 25 = 114118553609 is a prime.
It is a super-2 number, since 2×1141185536412 (a number of 23 digits) contains 22 as substring.
It is a junction number, because it is equal to n+sod(n) for n = 114118553594 and 114118553603.
It is not a weakly prime, because it can be changed into another prime (114119553641) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 57059276820 + 57059276821.
It is an arithmetic number, because the mean of its divisors is an integer number (57059276821).
Almost surely, 2114118553641 is an apocalyptic number.
It is an amenable number.
114118553641 is a deficient number, since it is larger than the sum of its proper divisors (1).
114118553641 is an equidigital number, since it uses as much as digits as its factorization.
114118553641 is an evil number, because the sum of its binary digits is even.
The product of its digits is 57600, while the sum is 40.
The spelling of 114118553641 in words is "one hundred fourteen billion, one hundred eighteen million, five hundred fifty-three thousand, six hundred forty-one".
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