Base | Representation |
---|---|
bin | 11001111100101010101001… |
… | …011001010010001101110001 |
3 | 112222001202222120220210022110 |
4 | 121330222221121102031301 |
5 | 104424221002444014213 |
6 | 1042414021043155533 |
7 | 33015623014456350 |
oct | 3174525131221561 |
9 | 488052876823273 |
10 | 114120123032433 |
11 | 333a9088389a81 |
12 | 109712b2375ba9 |
13 | 4b8a6349004bb |
14 | 202762ca91997 |
15 | d2d7d63775c3 |
hex | 67caa9652371 |
114120123032433 has 64 divisors (see below), whose sum is σ = 181748701532160. Its totient is φ = 62276366515968.
The previous prime is 114120123032411. The next prime is 114120123032491. The reversal of 114120123032433 is 334230321021411.
It is not a de Polignac number, because 114120123032433 - 28 = 114120123032177 is a prime.
It is a self number, because there is not a number n which added to its sum of digits gives 114120123032433.
It is not an unprimeable number, because it can be changed into a prime (114120123034433) by changing a digit.
It is a polite number, since it can be written in 63 ways as a sum of consecutive naturals, for example, 1259294598 + ... + 1259385216.
It is an arithmetic number, because the mean of its divisors is an integer number (2839823461440).
Almost surely, 2114120123032433 is an apocalyptic number.
It is an amenable number.
114120123032433 is a deficient number, since it is larger than the sum of its proper divisors (67628578499727).
114120123032433 is a wasteful number, since it uses less digits than its factorization.
114120123032433 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 94798.
The product of its (nonzero) digits is 10368, while the sum is 30.
Adding to 114120123032433 its reverse (334230321021411), we get a palindrome (448350444053844).
The spelling of 114120123032433 in words is "one hundred fourteen trillion, one hundred twenty billion, one hundred twenty-three million, thirty-two thousand, four hundred thirty-three".
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