Base | Representation |
---|---|
bin | 1010011000010001011101… |
… | …1100110110010101001011 |
3 | 1111101222200101001021200201 |
4 | 2212010113130312111023 |
5 | 2443434011103402021 |
6 | 40134353430313031 |
7 | 2255333003412646 |
oct | 246042734662513 |
9 | 44358611037621 |
10 | 11412121544011 |
11 | 36aa943109781 |
12 | 13438b44b8777 |
13 | 64a20a141836 |
14 | 2b64c7554a5d |
15 | 14bcc7331591 |
hex | a611773654b |
11412121544011 has 2 divisors, whose sum is σ = 11412121544012. Its totient is φ = 11412121544010.
The previous prime is 11412121543997. The next prime is 11412121544027. The reversal of 11412121544011 is 11044512121411.
11412121544011 is digitally balanced in base 2, because in such base it contains all the possibile digits an equal number of times.
It is a weak prime.
It is a cyclic number.
It is not a de Polignac number, because 11412121544011 - 211 = 11412121541963 is a prime.
It is not a weakly prime, because it can be changed into another prime (11412121544081) by changing a digit.
It is a polite number, since it can be written as a sum of consecutive naturals, namely, 5706060772005 + 5706060772006.
It is an arithmetic number, because the mean of its divisors is an integer number (5706060772006).
Almost surely, 211412121544011 is an apocalyptic number.
11412121544011 is a deficient number, since it is larger than the sum of its proper divisors (1).
11412121544011 is an equidigital number, since it uses as much as digits as its factorization.
11412121544011 is an evil number, because the sum of its binary digits is even.
The product of its (nonzero) digits is 1280, while the sum is 28.
Adding to 11412121544011 its reverse (11044512121411), we get a palindrome (22456633665422).
The spelling of 11412121544011 in words is "eleven trillion, four hundred twelve billion, one hundred twenty-one million, five hundred forty-four thousand, eleven".
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