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114121224343 = 716303032049
BaseRepresentation
bin110101001001000100…
…1111011000010010111
3101220120022012212100201
41222102021323002113
53332210013134333
6124232045521331
711150013254530
oct1522211730227
9356508185321
10114121224343
1144442501a45
121a14ab73247
13a9b92838a9
145748691687
152e7dd1617d
hex1a9227b097

114121224343 has 4 divisors (see below), whose sum is σ = 130424256400. Its totient is φ = 97818192288.

The previous prime is 114121224223. The next prime is 114121224491. The reversal of 114121224343 is 343422121411.

It is a happy number.

It is a semiprime because it is the product of two primes.

It is a cyclic number.

It is not a de Polignac number, because 114121224343 - 221 = 114119127191 is a prime.

It is a Duffinian number.

It is a congruent number.

It is not an unprimeable number, because it can be changed into a prime (114121224143) by changing a digit.

It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 8151516018 + ... + 8151516031.

It is an arithmetic number, because the mean of its divisors is an integer number (32606064100).

Almost surely, 2114121224343 is an apocalyptic number.

114121224343 is a deficient number, since it is larger than the sum of its proper divisors (16303032057).

114121224343 is an equidigital number, since it uses as much as digits as its factorization.

114121224343 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 16303032056.

The product of its digits is 4608, while the sum is 28.

Adding to 114121224343 its reverse (343422121411), we get a palindrome (457543345754).

The spelling of 114121224343 in words is "one hundred fourteen billion, one hundred twenty-one million, two hundred twenty-four thousand, three hundred forty-three".

Divisors: 1 7 16303032049 114121224343