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1141214115 = 35234916737
BaseRepresentation
bin100010000000101…
…1000101110100011
32221112101200110110
41010001120232203
54314122322430
6305124102403
740165105566
oct10401305643
92845350413
101141214115
11536205068
1227a234a03
13152581032
14ab7ca4dd
156a2c77b0
hex44058ba3

1141214115 has 32 divisors (see below), whose sum is σ = 1909495296. Its totient is φ = 580912640.

The previous prime is 1141214111. The next prime is 1141214141. The reversal of 1141214115 is 5114121411.

It is not a de Polignac number, because 1141214115 - 22 = 1141214111 is a prime.

It is a junction number, because it is equal to n+sod(n) for n = 1141214091 and 1141214100.

It is not an unprimeable number, because it can be changed into a prime (1141214111) by changing a digit.

It is a polite number, since it can be written in 31 ways as a sum of consecutive naturals, for example, 166027 + ... + 172763.

It is an arithmetic number, because the mean of its divisors is an integer number (59671728).

Almost surely, 21141214115 is an apocalyptic number.

1141214115 is a gapful number since it is divisible by the number (15) formed by its first and last digit.

1141214115 is a deficient number, since it is larger than the sum of its proper divisors (768281181).

1141214115 is a wasteful number, since it uses less digits than its factorization.

1141214115 is an evil number, because the sum of its binary digits is even.

The sum of its prime factors is 7259.

The product of its digits is 160, while the sum is 21.

The square root of 1141214115 is about 33781.8607391600. The cubic root of 1141214115 is about 1045.0146484214.

Adding to 1141214115 its reverse (5114121411), we get a palindrome (6255335526).

The spelling of 1141214115 in words is "one billion, one hundred forty-one million, two hundred fourteen thousand, one hundred fifteen".

Divisors: 1 3 5 15 23 69 115 345 491 1473 2455 6737 7365 11293 20211 33685 33879 56465 101055 154951 169395 464853 774755 2324265 3307867 9923601 16539335 49618005 76080941 228242823 380404705 1141214115