Base | Representation |
---|---|
bin | 10000100110110101101… |
… | …011011101011001000001 |
3 | 11001002200012020022202021 |
4 | 100212311223131121001 |
5 | 122144201341331423 |
6 | 2232133333121441 |
7 | 145310233236202 |
oct | 20466553353101 |
9 | 4032605208667 |
10 | 1141214402113 |
11 | 3aaa93862345 |
12 | 165212489281 |
13 | 83801625466 |
14 | 3d3410735a9 |
15 | 1ea43dba95d |
hex | 109b5add641 |
1141214402113 has 4 divisors (see below), whose sum is σ = 1152979499140. Its totient is φ = 1129449305088.
The previous prime is 1141214402033. The next prime is 1141214402147. The reversal of 1141214402113 is 3112044121411.
It is a semiprime because it is the product of two primes.
It can be written as a sum of positive squares in 2 ways, for example, as 883406370609 + 257808031504 = 939897^2 + 507748^2 .
It is a cyclic number.
It is a de Polignac number, because none of the positive numbers 2k-1141214402113 is a prime.
It is a Duffinian number.
It is not an unprimeable number, because it can be changed into a prime (1141214402173) by changing a digit.
It is a polite number, since it can be written in 3 ways as a sum of consecutive naturals, for example, 5882548368 + ... + 5882548561.
It is an arithmetic number, because the mean of its divisors is an integer number (288244874785).
Almost surely, 21141214402113 is an apocalyptic number.
It is an amenable number.
1141214402113 is a deficient number, since it is larger than the sum of its proper divisors (11765097027).
1141214402113 is an equidigital number, since it uses as much as digits as its factorization.
1141214402113 is an evil number, because the sum of its binary digits is even.
The sum of its prime factors is 11765097026.
The product of its (nonzero) digits is 768, while the sum is 25.
Adding to 1141214402113 its reverse (3112044121411), we get a palindrome (4253258523524).
The spelling of 1141214402113 in words is "one trillion, one hundred forty-one billion, two hundred fourteen million, four hundred two thousand, one hundred thirteen".
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